Consider the following unbalanced half-reaction: $C r O_{2} + ? O H \to C r O_{4}^{- 2} + ? H_{2} O + 3 e^{-}$ $CrO_2 + ?OH -> CrO_4^(-2) + ?H_2O + 3e^-$ . If the equation were balanced, what would be the coefficient of the water molecule?

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Answer 1 · 2016-07-01T14:44:35

$C r O_{2} + 4 O H^{-} \to C r O_{4}^{- 2} + 2 H_{2} O + 2 e^{-}$ $CrO_2 + 4OH ^"-" -> CrO_4^(-2) + 2H_2O + 2e^-$

The equation should be as follows
$C r O_{2} + 4 O H^{-} \to C r O_{4}^{- 2} + 2 H_{2} O + 2 e^{-}$ $CrO_2 + 4OH ^"-" -> CrO_4^(-2) + 2H_2O + 2e^-$

Consider the following unbalanced half-reaction: CrO2+?OH→CrO−24+?H2O+3e−CrO_2 + ?OH -> CrO_4^(-2) + ?H_2O + 3e^-. If the equation were balanced, what would be the coefficient of the water molecule?