Could someone help me to do the mentioned equation,please?

#e^(2ln(tan5x))=?#

1 Answer
Jim G.
Dec 4, 2017

#10tan5xsec^2 5x#

Explanation:

#"assuming you require the derivative"#

#"note that "e^lnx=x#

#rArre^(2ln(tan5x))=e^(ln(tan5x)^2)=(tan5x)^2#

#"differentiate using the "color(blue)"chain rule"#

#"given "y=f(g(x))" then "#

#dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"#

#d/dx((tan5x)^2)#

#=2tan5x xxd/dx(tan5x)#

#=2tan5xsec^2 5x xxd/dx(5x)#

#=10tan5xsec^2 5x#

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