Could the points (-4,3), (-1,1) and (1,3) form the vertices of a right triangle?

1 Answer
Dec 11, 2016

No

Explanation:

Using distance formula (x2x1)2+(y2y1)2, the distance between (-4,3) and (-1,1) would be 32+(2)2=13, distance between (-1,1) and (1,3) would be 22+22=8, and the distance between (-4,3) and (1,3) would be 52+02=25

Now the sum of the squares of any of these two distances does not equal to the square of the the third distance. Hence the triangle is not a right triangle.