Differentiate y = 9/(2x + 3y=92x+3?

1 Answer
Jim G.
May 8, 2018

dy/dx=-18/(2x+3)^2dydx=−18(2x+3)2

Explanation:

"differentiate using the "color(blue)"chain rule"differentiate using the chain rule

"given "y=f(g(x))" then"given y=f(g(x)) then

dy/dx=f'(g(x))xxg'(x)

"here "y=9/(2x+3)=9(2x+3)^-1

rArrdy/dx=-9(2x+3)^-2xxd/dx(2x+3)

color(white)(rArrdy/dx)=-9(2x+3)^-2xx2

color(white)(rArrdy/dx)=-18/(2x+3)^2

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