Do acid base reactions always produce salt?

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Do acid base reactions always produce salt?

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Answer 1 · 2016-06-30T16:46:25

Why yes, they does.

Explanation:

$Acid + Base \to Salt + Water$ $"Acid + Base "rarr" Salt + Water"$

Examples include:

$H X (a q) + N a O H (a q) \to N a X (a q) + H_{2} O (l)$ $HX(aq) + NaOH(aq) rarr NaX(aq) + H_2O(l)$

$N H_{4} X (a q) + N a O H (a q) \to N a X (a q) + H_{2} O (l) + N H_{3} (l)$ $NH_4X(aq) + NaOH(aq) rarr NaX(aq) + H_2O(l) +NH_3(l)$

$H_{2} S O_{4} (a q) + N a O H (a q) \to N a H S O_{4} (a q) + H_{2} O (l)$ $H_2SO_4(aq) + NaOH(aq)rarr NaHSO_4(aq) + H_2O(l)$

$H_{2} S O_{4} (a q) + 2 N a O H (a q) \to N a_{2} S O_{4} (a q) + 2 H_{2} O (l)$ $H_2SO_4(aq) + 2NaOH(aq)rarr Na_2SO_4(aq) + 2H_2O(l)$

$H_{3} P O_{4} (a q) + 2 N a O H (a q) \to N a_{2} H P O_{4} (a q) + 2 H_{2} O (l)$ $H_3PO_4(aq) + 2NaOH(aq) rarr Na_2HPO_4(aq) + 2H_2O(l)$

$H C \equiv N (a q) + K O H (a q) \to K C \equiv N (a q) + H_{2} O (l)$ $HC-=N(aq) + KOH(aq) rarrKC-=N(aq) + H_2O(l)$

Since I have deployed a strong base in each case, the reaction would lie strongly to the right. Weaker acids/weaker bases would give equilibrium mixtures. Mind you, $^{-} C \equiv N$ $""^(-)C-=N$ and $N H_{3}$ $NH_3$ , would both cause some hydrolysis.

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Do acid base reactions always produce salt?

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