During an experiment, 30 mL of a gas is collected at 401 kPa. What will the volume be at standard pressure?

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During an experiment, 30 mL of a gas is collected at 401 kPa. What will the volume be at standard pressure?

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Answer 1 · 2016-08-25T03:25:25

Volume = 119 ml If the temperature does not change it is possible to calculate the new volume using Boyle's Law.

Explanation:

If the temperature changes the volume will also change. The question does not give any information regarding the temperature so it is necessary to assume the temperature does not change in this problem.

Boyle's Law states that pressure and volume are inversely related so in this problem as the pressure decreases the volume will increase.

Boyle's Law $\frac{V_{1}}{V_{2}} = \frac{P_{2}}{P_{1}}$ $V_1/ V_2 = P_2/ P_1$

$V_{1} = 30 m l$ $V_1 = 30 ml$
$V_{2} = u n k n o w n$ $V_2 = unknown$
$P_{1} = 401 k p a$ $P_1 = 401 kpa$
$P_{2} = 101 k p a$ $P_2 = 101 kpa$ 101 kpa is the standard pressure.

$\frac{30}{V_{2}} = \frac{101}{401}$ $30/V_2 = 101/401$ solving for $V_{2}$ $V_2$ gives

$V_{2} = 30 m l \times \frac{401}{101}$ $V_2 = 30 ml xx 401/101$

$V_{2}$ $V_2$ = 119 ml

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During an experiment, 30 mL of a gas is collected at 401 kPa. What will the volume be at standard pressure?

1 Answer

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