Evaluate the following definite integral to three significant digits. I have been using rule #int ((du)/u) = ln |u| + C # And come out with an answer of 0.546. The answer is 0.732?

Question

#int_0^1 (dx)/(sqrt(3-2x^2))#

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Answer 1 · 2018-03-26T06:37:11

#1/sqrt2 sin^-1(sqrt(2/3))~~0.676# (to three significant digits)

#int_0^1 (dx)/(sqrt(3-2x^2)) = 1/sqrt2 int_0^1 (dx)/(sqrt(3/2-x^2)) = 1/sqrt2 sin^-1(sqrt(2/3)x)_0^1=1/sqrt2 sin^-1(sqrt(2/3))~~0.6755#