Exactly one mole of an ideal gas is contained in a 2.00 liter container at 1,000 K. What is the pressure exerted by this gas?

Question

Exactly one mole of an ideal gas is contained in a 2.00 liter container at 1,000 K. What is the pressure exerted by this gas?

1 Answer

Impact of this question

3331 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-01T06:06:43

Over $40 \cdot a t m$ $40*atm$ . We follow the ideal gas equation

Explanation:

$P = \frac{n R T}{V}$ $P=(nRT)/V$ $=$ $=$ $(1*cancel(mol)xx0.0821*cancelL*atm*cancel(K^-1)*cancel(mol^-1)xx1000*cancel(K))/(2.00*cancelL)$ $=$ $??*atm$

I hope the container is strong.

Science

Math

Humanities

... and beyond

Exactly one mole of an ideal gas is contained in a 2.00 liter container at 1,000 K. What is the pressure exerted by this gas?

1 Answer

Explanation:

Related questions

Impact of this question