Find a quadratic function with zeros at #a+4# and #2a# where #a# is a constant. Write the function in standard form #f(x)=ax^2+bx+c#, and give the values of #a#, #b# and #c#. Assume the leading coefficient is 1?
1 Answer
Feb 20, 2018
with coefficients
Explanation:
A polynomial has a zero
So given zeros
So we can write:
#f(x) = (x-(a+4))(x-2a)#
#color(white)(f(x)) = x^2-(3a+4)x+(2a^2+8a)#
So the three coefficients are