Find all real numbers in the interval $[0, 2 π)$ $[0, 2pi)$ round to the nearest tenth? $3 {sin}^{2} x = sin x$ $3 sin^2x=sin x$

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Find all real numbers in the interval $[0, 2 π)$ $[0, 2pi)$ round to the nearest tenth? $3 {sin}^{2} x = sin x$ $3 sin^2x=sin x$

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Answer 1 · 2018-04-17T12:07:15

$x = 0^{c}, {0.34}^{c}, π^{c}, {2.80}^{c}$ $x=0^c,0.34^c,pi^c,2.80^c$

Explanation:

Rearrange to get:
$3 {sin}^{2} x - sin x = 0$ $3sin^2x-sinx=0$

$sin x = \frac{1 \pm \sqrt{1^{2}}}{6}$ $sinx=(1+-sqrt(1^2))/6$

$sin x = \frac{1 + 1}{6} or \frac{1 - 1}{6}$ $sinx=(1+1)/6 or (1-1)/6$

$sin x = \frac{2}{6} or \frac{0}{6}$ $sinx=2/6 or 0/6$

$sin x = \frac{1}{3} or 0$ $sinx=1/3or0$

$x = {sin}^{- 1} (0) = 0, π - 0 = 0^{c}, π^{c}$ $x=sin^-1(0)=0, pi-0=0^c,pi^c$
or
$x = {sin}^{- 1} (\frac{1}{3}) = 0.34, π - 0.34 = {0.34}^{c}, {2.80}^{c}$ $x=sin^-1(1/3)=0.34, pi-0.34=0.34^c,2.80^c$

$x = 0^{c}, {0.34}^{c}, π^{c}, {2.80}^{c}$ $x=0^c,0.34^c,pi^c,2.80^c$

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Find all real numbers in the interval $[0, 2 π)$ $[0, 2pi)$ round to the nearest tenth? $3 {sin}^{2} x = sin x$ $3 sin^2x=sin x$

1 Answer

Explanation:

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Science

Math

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Find all real numbers in the interval [0,2π)[0, 2pi) round to the nearest tenth? 3sin2x=sinx3 sin^2x=sin x

1 Answer

Explanation:

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Find all real numbers in the interval $[0, 2 π)$ $[0, 2pi)$ round to the nearest tenth? $3 {sin}^{2} x = sin x$ $3 sin^2x=sin x$