Find out the value of x and y #xy=6# #2x-y=3# ???
Thanks in advance !
Thanks in advance !
1 Answer
Oct 12, 2017
If would use substitution. If we rearrange the second equation for
#2x - 3 = y#
Accordingly:
#x(2x -3) = 6#
#2x^2 - 3x - 6 =0#
By the quadratic formula, we get:
#x = (-(-3) +- sqrt(3^2 - 4 * 2 * -6))/(2 * 2)#
#x= (3 +-sqrt(57))/4#
We can now solve for
#y = 2((3 + sqrt(57))/4) - 3 #
#y = (3 + sqrt(57) - 6)/2#
#y = (sqrt(57) - 3)/2#
Now for the other solution, we get:
#y = (-sqrt(57) - 3)/2#
So our solutions are
Hopefully this helps!