Find the partial sum?

Question

$1 \sum n = - 2 (n + 6)$ $sum_(n=-2)^1(n+6)$

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Answer 1 · 2018-05-28T01:13:58

$1 \sum n = - 2 (n + 6) = 22$ $sum_(n=-2)^1(n+6) = 22$

We seek:

$S = 1 \sum n = - 2 (n + 6)$ $S = sum_(n=-2)^1(n+6)$

If we expand the summation this becomes:

$S = (- 2 + 6) + (- 1 + 6) + (0 + 6) + (1 + 6)$ $S = (-2+6) + (-1+6) + (0+6) + (1+6)$

$\ \ = 4 + 5 + 6 + 7$

$\ \ = 22$