Find The Sum Of All Solutions To The Equation #3x(x+4)=66#. Help, Please?

1 Answer
Dec 21, 2017

#-4#

Explanation:

Start with #3x(x+4)=66#

divide through by 3:

#x(x+4)=22#

expand the left side:

#x^2+4x=22#

subtract 22 from both sides:

#x^2+4x-22=0#.

Use the quadratic formula: #x=(-b\pmsqrt(b^2-4ac))/(2a)#:

#x=(-4+sqrt(4^2-4(1)(-22)))/(2)=-2+sqrt(26)# or #x=(-4-sqrt(4^2-4(1)(-22)))/(2)=-2-sqrt(26)#

If we add those together the radicals cancel out:

#-2+sqrt(26) +(-2-sqrt(26)) = -4#, which is just actually the opposite of b/a: sum of roots is #-b/a#, but most of my students never remember that so they go through all the work I just did.