For an ideal gas, how do you calculate the pressure in atm if 8.25 x 10^-2 mol occupies 174 mL at 215°C?

1 Answer
May 9, 2016

P=(nRT)/V=??*atm

Explanation:

We have been quoted the moles, n, the temperature, 488*K on the absolute scale, the volume, 0.174*L. All we need to do is choose an appropriate gas constant. R=0.0821*L*atm*K^-1*mol^-1.

Thus, P=(8.25xx10^-2*molxx0.0821*(L*atm)/(K*mol)xx488*K)/(0.174*L) for an answer in atmospheres.

Thx to Shelby who pointed out an error on my part!