For each molecule of sulfuric acid, how many hydrogen ions are released in water?

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For each molecule of sulfuric acid, how many hydrogen ions are released in water?

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Answer 1 · 2017-04-06T19:34:34

Usually 2..........

Explanation:

The conjugate base of sulfuric, $H_{2} S O_{4}$ $H_2SO_4$ , is bisulfate, $H S O_{4}^{-}$ $HSO_4^-$ , which is itself a reasonably strong acid. In aqueous solution, the given equilibrium lies to the right:

$H_{2} S O_{4} (a q) + 2 H_{2} O (l) ⇌ 2 H_{3} O^{+} + S O_{4}^{2 -}$ $H_2SO_4(aq) + 2H_2O(l) rightleftharpoons2H_3O^+ + SO_4^(2-)$

As chemists, as physical scientists, we should seek out some quantitative data:

this site quotes $p K_{a_{1}} = - 3.0; p K_{a 2} = 1.99$ $pK_(a_1)=-3.0;pK_(a2)=1.99$ .

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For each molecule of sulfuric acid, how many hydrogen ions are released in water?

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Explanation:

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