For f(m)=3m^2-5f(m)=3m25, how do you find f(4),f(-3),f(6)?

1 Answer
Jul 8, 2015

f(4) = 43f(4)=43
f(-3) = 22f(3)=22
f(6) = 102f(6)=102

Explanation:

Given f(color(red)(m))=3color(red)(m)^2-5f(m)=3m25

To evaluate f(color(red)()4)f(4) rewrite the given equation replacing each color(red)(m)m with color(red)(4)4 and perform the arithmetic.
color(white)("XXXX")XXXXf(color(red)(4)) = 3(color(red)(4))^2 -5f(4)=3(4)25
color(white)("XXXX")XXXXcolor(white)("XXXX")XXXX=3(16)-5=3(16)5
color(white)("XXXX")XXXXcolor(white)("XXXX")XXXX= 43=43

Similarly for f(color(red)(-3))f(3)
color(white)("XXXX")XXXXf(color(red)(-3)) = 3(color(red)(-3))^2-5f(3)=3(3)25
color(white)("XXXX")XXXXcolor(white)("XXXX")XXXX=3(9)-5=3(9)5
color(white)("XXXX")XXXXcolor(white)("XXXX")XXXX= 22=22

and for f(6)f(6)
color(white)("XXXX")XXXXf(color(red)(6)) = 3(color(red)(6))^2-5f(6)=3(6)25
color(white)("XXXX")XXXXcolor(white)("XXXX")XXXX=3(36)-6=3(36)6
color(white)("XXXX")XXXXcolor(white)("XXXX")XXXX= 102=102