Question

For `f(t)= (cos2t,sin^2t)` what is the distance between `f(pi/4)` and `f(pi)`?

Answer 1

Distance between `f(pi/4)` and `f(pi)` is `sqrt5/2`

Explanation:

As `f(t)=(cos2t,sin^2t)`

`f(pi/4)=(cos(pi/2),sin^2(pi/4))=(0,1/2)`

and `f(pi)=(cos2pi,sin^2pi)=(1,0)`

and distance between `f(pi/4)` and `f(pi)` is

`sqrt((1-0)^2+(0-1/2)^2)=sqrt(1+1/4)=sqrt5/2`