Question

For `f(t)= (t^3-t^2+1,t^2-t)` what is the distance between `f(2)` and `f(5)`?

Answer 1

`6 sqrt{265}`

Explanation:

`f(2) = (8 - 4 + 1, 4 - 2) = (5,2)`

`f(5) = (125-25+1,25-5) = (101,20)`

dist = #sqrt{96^2 + 18^2} = sqrt 9540 = sqrt{2 ^ 2 * 3 ^ 2 * 5 * 53 }#