For f(t)=(tt3,tt2+1) what is the distance between f(0) and f(1)?

1 Answer
Apr 19, 2016

The distance between f(0) and f(1) is 0.866.

Explanation:

The coordinates of point for f(0) is (003,002+1) or (0,0)

and for f(1) we have (113,112+1) or (12,12)

The distance between the two points is

(0(12))2+(012)2=14+12=34=32=1.7322=0.866