For $f (x) = | x | - 2$ $f(x)=abs[x]-2$ ; how do you find f(3),f(93) and f(-100)?

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Answer 1 · 2015-07-12T20:32:39

1, 91, 98

$f ($ $f($ thing $) = ∣$ $) = |$ thing $∣ - 2$ $| - 2$

$| 3 | - 2 = 3 - 2$ $|3| - 2 = 3 - 2$

$| 93 | - 2 = 93 - 2$ $|93| - 2 = 93 - 2$

$| - 100 | - 2 = 100 - 2$ $|-100|-2 = 100 - 2$

For f(x)=|x|−2f(x)=abs[x]-2; how do you find f(3),f(93) and f(-100)?