For Geometry lovers, help me solve this?

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1 Answer
Feb 15, 2018

Area 52.102 " cm"^2

Explanation:

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angleAOB=alpha=360^@/5=72^@
Area of DeltaOAB=A_1=1/2*7^2*sinalpha=1/2*49*sin72=23.3009 " cm"^2
tanalpha=(AT)/(OA),
=> AT=OA*tan72=7*tan72=21.5438 cm
Area of DeltaOAT=A_2=1/2*OA*AT=1/2*7*21.5438=75.4033 " cm"^2
=> Area of DeltaABT="shaded area"=A_2-A_1=75.4033-23.3009~~52.102 " cm"^@