For $h (x) = 19$ $h(x)=19$ ; how do you find h(4),h(-6),and h(12)?

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Answer 1 · 2015-07-09T13:15:21

# h(4) = h(-6) = h(12) = 19

Your function $h$ $h$ is constant : Whatever the number you choose, the result is always the same : $19$ $19$ , here.

graph{0x+19 [-19.91, 32.22, -1.68, 24.42]}

For h(x)=19h(x)=19h(x)=19; how do you find h(4),h(-6),and h(12)?