For $h(x)=x^4 -3$ ; how do you find f(4),f(-3),and f(6)?

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Answer 1 · 2015-07-27T12:38:48

You simply evaluate the function for $x=4$ , $x=-3$ , and $x=6$ .

Your function looks like this

$h(x) = x^4 - 3$

In order to find the value of $h$ in points $4$ , $-3$ , and $6$ , evaluate the function for these three values of $x$ .

Simply put, replace $x$ with these numbers and calculate $h$ .

$h(4) = color(blue)(4)^4 - 3 = 256 -3 = color(green)(253)$

$h(-3) = color(blue)((-3))^4 - 3 = 81 - 3 = color(green)(78)$

and finally

$h(6) = color(blue)(6)^4 - 3 = 1296 - 3 = color(green)(1293)$

For h(x)=x^4 -3h(x)=x^4 -3; how do you find f(4),f(-3),and f(6)?