Question

For `P(x)=3x^2-2x`; how do you find P(0),P(-2) and P(3)?

Answer 1

Given an equation defined with a variable place holder (in this case `x`), replace the variable place holder with specified value and evaluate to determine the value of the equation at that point.

Explanation:

If `P(color(red)(x)) = 3color(red)(x)^2-2color(red)(x)`

then

`P(color(red)(0)) = 3(color(red)(0))^2 - 2(color(red)(0)) = 0`

`P(color(red)(-2)) = 3(color(red)(-2))^2 -2(color(red)(-2)) = 12 +4 = 16`

`P(color(red)(3)) = 3(color(red)(3))^2-2(color(red)(3) )= 27-6 = 21`