For the function f(x) = x^2 - 2x + 1f(x)=x22x+1, how do you find f(0)?

1 Answer
Jun 16, 2016

f(0)=1f(0)=1

Explanation:

Given
color(white)("XXX")f(color(red)(x))=color(red)(x)^2-2color(red)(x)+1XXXf(x)=x22x+1

To find f(color(blue)(0))f(0) replace color(red)(x)x with color(blue)(0)0
color(white)("XXX")f(color(blue)(0))=color(blue)(0)^2-2(color(blue)(0))+1 =color(green)(1)XXXf(0)=022(0)+1=1