For the function $f (x) = x^{2} - 5$ $f(x)=x^2-5$ , how do you find $f (x + h)$ $f(x+h)$ ?

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Answer 1 · 2016-12-07T18:46:42

Please see the explanation.

Given $f (x) = x^{2} - 5$ $f(x) = x^2 - 5$

Substitute x + h for every x:

$f (x + h) = {(x + h)}^{2} - 5$ $f(x + h) = (x + h)^2 - 5$

Expand the square:

$f (x + h) = x^{2} + 2 h x + h^{2} - 5$ $f(x + h) = x^2 + 2hx + h^2 - 5$

For the function f(x)=x2−5f(x)=x^2-5, how do you find f(x+h)f(x+h)?