For what values of x is f(x)=-x^4+4x^3-2x^2-x+5 concave or convex?

1 Answer
Jun 1, 2016

x < 1/3 (3 - sqrt[6]) -> "convexity"
1/3 (3 - sqrt[6]) < x < 1/3 (3 + sqrt[6])->"concavity"
1/3 (3 + sqrt[6])< x->"convexity"

Explanation:

For f(x) the local concavity/convexity is given by the sign of

(d^2f)/(dx^2)(x).

For f(x) = -x^4 + 4 x^3 - 2 x^2 - x + 5
we have (d^2f)/(dx^2)(x)=-4 + 24 x - 12 x^2.

If (d^2f)/(dx^2)(x) <0 the local curvature is qualified as convex
otherwise if (d^2f)/(dx^2)(x) > 0 concave.

Extracting the roots of

-4 + 24 x - 12 x^2= 0

we get

{(x = 1/3 (3 - sqrt[6])),(x = 1/3 (3 + sqrt[6])):}

x < 1/3 (3 - sqrt[6]) -> "convexity"
1/3 (3 - sqrt[6]) < x < 1/3 (3 + sqrt[6])->"concavity"
1/3 (3 + sqrt[6])< x->"convexity"

blue f(x), pink (d^2f)/(dx^2)(x)
enter image source here