For what values of x is f(x)=(x+6)(x-1)(x+3)f(x)=(x+6)(x1)(x+3) concave or convex?

1 Answer
Dec 8, 2017

f(x)f(x) is concave for x in (-oo, -8/3)x(,83) and convex for x in (-8/3, oo)x(83,)

Explanation:

A function is convex where its second derivative is positive and concave where its second derivative is negative. If its second derivative is 00, then the function may be concave, convex or neither. Commonly such will be a point of inflexion.

Given:

f(x) = (x+6)(x-1)(x+3)f(x)=(x+6)(x1)(x+3)

color(white)(f(x)) = x^3+8x^2+9x-18f(x)=x3+8x2+9x18

We find:

f'(x) = 3x^2+16x+9

and:

f''(x) = 6x+16

Hence f(x) is concave for x in (-oo, -8/3) and convex for x in (-8/3, oo)

It has a point of infexion at x=-8/3

graph{(x+6)(x-1)(x+3) [-8.21, 1.79, -25, 22]}