Question

For which non-zero real values of `x` is `-x^(-6) = (-x)^(-6)` ?

Answer 1

None

Explanation:

If `x != 0` then `x^2 > 0` and we find:

`-x^(-6) = -1/(x^2)^3 < 0`

`(-x)^(-6) = 1/((-x)^2)^3 = 1/(x^2)^3 > 0`

So they cannot be equal.