For $y = x^2 - 2$ , if the x-values are -3, -2, 0, 1, 2 what are the y values?

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Answer 1 · 2018-03-13T18:30:37

$y_(-3)=7$
$y_(-2)=2$
$y_(0)=-2$
$y_(1)=-1$
$y_(2)=2$

$y = x^2 - 2$

$y_((-3)) = (-3)^2-2 = 9-2 = 7$
$y_((-3))=7$

$y_((-2))=2$
$y_(0)=-2$
$y_(1)=-1$
$y_(2)=2$

Answer 2 · 2018-03-13T18:50:09

See below...

By plugging in the corresponding $x$ values, we can get the $y$ value, as the answer is equal to the $y$ value.

When:

$x=-3,-2,0,1,2$ Shown by the equation, $y=x^2-2$ . Just plug in the corresponding $x$ value, to obtain the $y$ value.

$therefore$ when $x=-3$ $y=(-3)^2-2=9-2=7$ remembering a $- xx - =+$

when $x=-2$

$y=(-2)^2-2=4-2=2$

when $x=0$

$y=0^3-2=0-2=-2$

when $x=1$

$y=1^2-2=1-2=-1$

when $x=2$

$y=2^2-2=4-2=2$

For y = x^2 - 2y = x^2 - 2, if the x-values are -3, -2, 0, 1, 2 what are the y values?