Given 3-x where $x \leq 2$ $x <= 2$ and $x^{2}$ $x^2$ where $x > 2$ $x >2$ , how do you find f(6)?

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Answer 1 · 2016-06-10T07:53:29

The value is $f (6) = 36$ $f(6)=36$

The function is:

$f(x)={(3-x , x<=2),(x^2,x>2):}$

The first step of calculating the value of such piecewise function is to find in which interval is the argument located:

Since $6>2$ , the argument belongs to the second interval, so you have to apply the formula $f(x)=x^2$ .

$f(6)=6^2=36$

Given 3-x where x <= 2x≤2x <= 2 and x^2x2x^2 where x >2x>2x >2, how do you find f(6)?