Given $8 x + 4 y = 4$ $8x +4y= 4$ , how do you identify the slope and y-intercept?

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Answer 1 · 2016-11-15T22:06:23

$y = - 2 x + 1$ $y=-2x+1$

Slope $= - 2$ $=-2$
Y intercept $= 1$ $=1$

To find the slope and y-int, put it into slope-intercept form by isolating y.

$8 x + 4 y = 4$ $8x+4y=4$

Subtract $8 x$ $8x$ from each side:
$4 y = - 8 x + 4$ $4y=-8x+4$

Divide each side by $4$ $4$ :
$y = - 2 x + 1$ $y=-2x+1$

Slope $= - 2$ $=-2$
Y intercept $= 1$ $=1$

Given 8x+4y=48x +4y= 4, how do you identify the slope and y-intercept?