Given a right triangle $△ A B C$ $triangle ABC$ with $C = 90^{\circ}$ $C=90^circ$ , if a=6, b=8, how do you find c?

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Given a right triangle $△ A B C$ $triangle ABC$ with $C = 90^{\circ}$ $C=90^circ$ , if a=6, b=8, how do you find c?

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Answer 1 · 2018-02-02T19:56:55

$c = 10$ $c=10$

Explanation:

$using Pythagoras' theorem$ $"using "color(blue)"Pythagoras' theorem"$

$here c represents the hypotenuse since it is the side$ $"here c represents the hypotenuse since it is the side"$

$opposite ∠ C = 90^{\circ}$ $"opposite "angleC=90^@$

$\Rightarrow c^{2} = a^{2} + b^{2} \leftarrow Pythagoras' theorem$ $rArrc^2=a^2+b^2larrcolor(blue)"Pythagoras' theorem"$

$\Rightarrow c^{2} = 6^{2} + 8^{2} = 36 + 64 = 100$ $color(white)(rArrc^2)=6^2+8^2=36+64=100$

$c^{2} = 100 \Rightarrow c = \sqrt{100} = 10$ $c^2=100rArrc=sqrt100=10$

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Given a right triangle $△ A B C$ $triangle ABC$ with $C = 90^{\circ}$ $C=90^circ$ , if a=6, b=8, how do you find c?

1 Answer

Explanation:

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Given a right triangle $△ A B C$ $triangle ABC$ with $C = 90^{\circ}$ $C=90^circ$ , if a=6, b=8, how do you find c?