Given $f (x) = \frac{1}{x - 2}$ $f(x)=1/(x-2)$ , how do you find (f(f(1/2))?

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Answer 1 · 2016-03-12T06:08:16

$= - \frac{3}{8}$ $=-3/8$

$f(x)=1/(x-2)......(1)$
$f(1/2)=1/(1/2-2)=1/((1-4)/2)=1/(-3/2)=-2/3$
$:.f(f(1/2))=1/(f(1/2)-2)=1/(-2/3-2)=1/(-8/3)=-3/8$

Given f(x)=1/(x-2)f(x)=1x−2f(x)=1/(x-2), how do you find (f(f(1/2))?