Given $f (x) = 2 (3 x + 4) - 6$ $f(x)=2(3x+4)-6$ , how do you find the y intercept?

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Answer 1 · 2018-05-08T04:53:48

Simplify the equation to get $6 x + 2$ $6x+2$ , meaning the $y$ $y$ -int. is $(0, 2)$ $(0,2)$ .

The equation in the question has not yet been simplified down yet. We want to get it into slope-intercept form, or

$y = m x + b$ $y=mx+b$

So we multiply out $2 (3 x + 4)$ $2(3x+4)$ and get

$y = 6 x + 8 - 6$ $y = 6x+8 - 6$

Now we add in the $- 6$ $-6$ and our equation should look like

$y = 6 x + 8 - 6$ $y=6x+8-6$

We know that $8 - 6$ $8-6$ is $2$ $2$ , so our $b$ $b$ value, i.e. the $y$ $y$ -intercept, is $2$ $2$ and $m$ $m$ (the slope) is $6$ $6$ .

The final product should look like:

$y = 6 x + 2$ $y=6x+2$

Hence, the $y$ $y$ -intercept is $(0, 2)$ $(0,2)$ .

Hope this helped.

Given f(x)=2(3x+4)-6f(x)=2(3x+4)−6f(x)=2(3x+4)-6, how do you find the y intercept?