Given: $f(x) = 2+ sqrt(-3x+1)$ , $q(x) = (5x)/(x+2)$ , and $m(x) = abs(7 - x^2) + x$ , how do you find f(-33)?

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Answer 1 · 2015-06-10T10:34:02

You can simply substitute x with -33 in f(x) function:
$f(-33)=12$ .

$f(x)=2+sqrt(−3x+1)$

$q(x)=(5x)/(x+2)$
$m(x)=∣7−x^2∣+x$

How do you find f(-33)?
$f(-33)=2+sqrt(-3*-33+1)=2+sqrt(100)=2+10=12$

Given: f(x) = 2+ sqrt(-3x+1)f(x) = 2+ sqrt(-3x+1), q(x) = (5x)/(x+2)q(x) = (5x)/(x+2), and m(x) = abs(7 - x^2) + xm(x) = abs(7 - x^2) + x, how do you find f(-33)?