Given: $f (x) = 2 + \sqrt{- 3 x + 1}$ $f(x) = 2+ sqrt(-3x+1)$ , $q (x) = \frac{5 x}{x + 2}$ $q(x) = (5x)/(x+2)$ , and $m (x) = ∣ ∣ 7 - x^{2} ∣ ∣ + x$ $m(x) = abs(7 - x^2) + x$ , how do you find $q (- 2)$ $q(-2)$ ?

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Given: $f (x) = 2 + \sqrt{- 3 x + 1}$ $f(x) = 2+ sqrt(-3x+1)$ , $q (x) = \frac{5 x}{x + 2}$ $q(x) = (5x)/(x+2)$ , and $m (x) = ∣ ∣ 7 - x^{2} ∣ ∣ + x$ $m(x) = abs(7 - x^2) + x$ , how do you find $q (- 2)$ $q(-2)$ ?

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Answer 1 · 2018-03-05T13:25:05

Are you sure this question is correct $q (- 2)$ $q(-2)$ is undefined

Explanation:

$q (x) = \frac{5 x}{x + 2} \Rightarrow q (- 2) = \frac{5 (- 2)}{- 2 + 2}$ $color(green)(q(color(red)(x))=(5color(red)(x))/(color(red)(x)+2) =>q(color(red)(-2)) =(5(color(red)(-2)))/(color(red)(-2)+2)$

But this has a denominator of 0 so is 'undefined' (not allowed).

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Given: $f (x) = 2 + \sqrt{- 3 x + 1}$ $f(x) = 2+ sqrt(-3x+1)$ , $q (x) = \frac{5 x}{x + 2}$ $q(x) = (5x)/(x+2)$ , and $m (x) = ∣ ∣ 7 - x^{2} ∣ ∣ + x$ $m(x) = abs(7 - x^2) + x$ , how do you find $q (- 2)$ $q(-2)$ ?

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Explanation:

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Given: f(x)=2+√−3x+1f(x) = 2+ sqrt(-3x+1), q(x)=5xx+2q(x) = (5x)/(x+2), and m(x)=∣∣7−x2∣∣+xm(x) = abs(7 - x^2) + x, how do you find q(−2)q(-2)?

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Explanation:

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Given: $f (x) = 2 + \sqrt{- 3 x + 1}$ $f(x) = 2+ sqrt(-3x+1)$ , $q (x) = \frac{5 x}{x + 2}$ $q(x) = (5x)/(x+2)$ , and $m (x) = ∣ ∣ 7 - x^{2} ∣ ∣ + x$ $m(x) = abs(7 - x^2) + x$ , how do you find $q (- 2)$ $q(-2)$ ?