Given f(x)= -2sin x, g(x)= sin 2x, how do you graph h(x)= (f+g)(x)?
1 Answer
Feb 16, 2016
I can show how it looks like..
Explanation:
the graph of
graph{((y+2*sin x))=0[-6,6,-3,3]}
the graph of
graph{((y-2sin xcos x))=0[-6,6,-3,3]}
the graph of
graph{((y+2sin x)(y-2sin x*cos x))=0[-6,6,-3,3]}
the graph of
graph{((y+2sin x)+(y-2sin x*cos x))=0[-6,6,-3,3]}