Given $f (x) = - \frac{3}{4} x - \frac{3}{5}$ $f(x)=-3/4x-3/5$ , for which value of x is f(x)=0?

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Answer 1 · 2016-11-15T12:58:59

$x = - \frac{12}{15}$ $x = -12/15$

To solve this problem equate $- \frac{3}{4} x - \frac{3}{5}$ $-3/4 x - 3/5$ to $0$ $0$ and solve for $x$ $x$ :

$0 = - \frac{3}{4} x - \frac{3}{5}$ $0 = -3/4 x - 3/5$

$0 + \frac{3}{5} = - \frac{3}{4} x - \frac{3}{5} + \frac{3}{5}$ $0 + 3/5 = -3/4 x - 3/5 + 3/5$

$\frac{3}{5} = - \frac{3}{4} x$ $3/5 = -3/4 x$

$- \frac{4}{3} \cdot \frac{3}{5} = - \frac{4}{3} \cdot - \frac{3}{4} x$ $-4/3 * 3/5 = -4/3 * -3/4 x$

$- \frac{12}{15} = 1 x$ $-12/15 = 1x$

$x = - \frac{12}{15}$ $x = -12/15$

Given f(x)=−34x−35f(x)=-3/4x-3/5, for which value of x is f(x)=0?