Given $f (x) = 3 x + 5$ $f(x)=3x+5$ and $g (x) = - 8 x - 10$ $g (x)= -8x- 10$ , how do you find f(x)+g(x), f(x)-g(x), f(x)*g(x), $f (x) \div g (x)$ $f(x)divg(x)$ ?

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Answer 1 · 2018-05-29T15:59:48

see below....

$f (x) + g (x) = 3 x + 5 - 8 x - 10$ $f(x)+g(x)=3x+5-8x-10$

$f (x) + g (x) = - 5 x - 7$ $f(x)+g(x)=-5x-7$

$- - - - - - - - - - - - - - - - - - -$ $-------------------$

$f (x) - g (x) = 3 x + 5 - (- 8 x - 10)$ $f(x)-g(x)=3x+5-(-8x-10)$

$f (x) - g (x) = 3 x + 5 + 8 x + 10$ $f(x)-g(x)=3x+5+8x+10$

$f (x) - g (x) = 11 x + 15$ $f(x)-g(x)=11x+15$

$- - - - - - - - - - - - - - - - - - -$ $-------------------$

$f (x) \cdot g (x) = (3 x + 5) (- 8 x - 10)$ $f(x)*g(x)=(3x+5)(-8x-10)$

$f (x) \cdot g (x) = - 24 x^{2} - 70 x - 50$ $f(x)*g(x)=-24x^2-70x-50$

$- - - - - - - - - - - - - - - - - - -$ $-------------------$

$\frac{f (x)}{g (x)} = \frac{3 x + 5}{- 8 x - 10}$ $f(x)/g(x)=(3x+5)/(-8x-10)$

$\frac{f (x)}{g (x)} = - \frac{3 x + 5}{2 (4 x + 5)}$ $f(x)/g(x)=-(3x+5)/(2(4x+5))$

Given f(x)=3x+5f(x)=3x+5f(x)=3x+5 and g (x)= -8x- 10g(x)=−8x−10g (x)= -8x- 10, how do you find f(x)+g(x), f(x)-g(x), f(x)*g(x), f(x)divg(x)f(x)÷g(x)f(x)divg(x)?