Given f(x)=4x-3, g(x)=1/x and h(x)= x^2-x, how do you find f [h(4)]?

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Answer 1 · 2017-10-09T22:59:32

$f [h (4)] = 45$ $f[h(4)]=45$

First, you need to find $h (4)$ $h(4)$ , by subbing in $4$ $4$ every time you see $x$ $x$ .

$h (x) = x^{2} - x$ $h(x)= x^2-x$

$h (4) = 4^{2} - 4$ $h(4)= 4^2-4$

$h (4) = 16 - 4$ $h(4)= 16-4$

$therefore h(4)=12$

Now that we have $h(4)$ , we can figure out $f[h(4)]$ .

$f(x)=4x-3$

$f[h(4)]=4x-3$

$f(12)=4(12)-3$

$f(12)=48-3$

$therefore f[h(4)]=45$