Question

Given `f(x)= e^x ln(x)` how do you find find f'(1)?

Answer 1

`f'(x)=e`

Explanation:

As `f(x)=e^xlnx`

`f'(x)=e^x xx1/x+e^xlnx`

Hence `f'(x)=e^1 xx1/1+e^1xxln1`

= `exx1+exx0=e`