Given $f (x) = \sqrt[3]{x - 8}$ $f(x)=root3(x-8)$ how do you find f(-208) and f(8)?

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Given $f (x) = \sqrt[3]{x - 8}$ $f(x)=root3(x-8)$ how do you find f(-208) and f(8)?

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Answer 1 · 2016-12-01T12:22:31

$f (- 208) = - 6$ $f (- 208) = - 6$
$f (8) = 0$ $f (8) = 0$

Explanation:

To evaluate $f (x)$ $f (x)$ just substitute $x$ $x$ in $f$ $f$ expression...

$f (x) = \sqrt[3]{x - 8} \Rightarrow f (- 208) = \sqrt[3]{- 208 - 8} = \sqrt[3]{- 216} = \sqrt[3]{{(- 6)}^{3}} = - 6$ $f (x) = root(3) {x - 8} rArr f (- 208) = root(3) {- 208 - 8} = root(3) {- 216} = root(3) {(- 6)^3} = - 6$

$f (x) = \sqrt[3]{x - 8} \Rightarrow f (8) = \sqrt[3]{8 - 8} = \sqrt[3]{0} = 0$ $f (x) = root(3) {x - 8} rArr f (8) = root(3) {8 - 8} = root(3) 0 = 0$

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Given $f (x) = \sqrt[3]{x - 8}$ $f(x)=root3(x-8)$ how do you find f(-208) and f(8)?

1 Answer

Explanation:

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Given f(x)=3√x−8f(x)=root3(x-8) how do you find f(-208) and f(8)?

1 Answer

Explanation:

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Given $f (x) = \sqrt[3]{x - 8}$ $f(x)=root3(x-8)$ how do you find f(-208) and f(8)?