Given $f (x) = \frac{x^{2}}{x + 2}$ $f(x)= x^2/(x+2)$ how do you find $f (x + 2)$ $f(x+2)$ ?

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Answer 1 · 2018-06-27T07:42:40

$f (x) = \frac{x^{2}}{x + 2}$ $f(x)=x^2/(x+2)$

$f (x + 2) = \frac{{(x + 2)}^{2}}{x + 2 + 2} = \frac{{(x + 2)}^{2}}{x + 4}$ $f(x+2)=(x+2)^2/(x+2+2)=(x+2)^2/(x+4)$

Given f(x)=x2x+2f(x)= x^2/(x+2) how do you find f(x+2)f(x+2)?