Given $f (x) = x^{2} - x$ $f(x) = x^2 - x$ and g(x) = 3x + 1, how do you determine f( g (x) )?

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Given $f (x) = x^{2} - x$ $f(x) = x^2 - x$ and g(x) = 3x + 1, how do you determine f( g (x) )?

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Answer 1 · 2018-05-17T11:22:06

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Explanation:

$f (g (x)) = f (3 x + 1) = {(3 x + 1)}^{2} - (3 x + 1) = 9 x^{2} + 6 x + 1 - 3 x - 1 = 9 x^{2} + 3 x$ $f(g(x))=f(3x+1)=(3x+1)^2-(3x+1)=9x^2+6x+1-3x-1=9x^2+3x$

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Given $f (x) = x^{2} - x$ $f(x) = x^2 - x$ and g(x) = 3x + 1, how do you determine f( g (x) )?

1 Answer

Explanation:

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Given $f (x) = x^{2} - x$ $f(x) = x^2 - x$ and g(x) = 3x + 1, how do you determine f( g (x) )?