Given $g (x) = - 2 x^{2} - 9$ $g(x) = -2x^2 - 9$ how do you find g(3)?

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Given $g (x) = - 2 x^{2} - 9$ $g(x) = -2x^2 - 9$ how do you find g(3)?

2 Answers

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Answer 1 · 2017-03-16T00:39:58

$g (3) = - 27$ $g(3)=-27$

Explanation:

You would substitute 3 for each x...
$- 2 {(3)}^{2} - 9$ $-2(3)^2-9$
$- 2 (9) - 9$ $-2(9)-9$
$- 18 - 9$ $-18-9$
$- 27$ $-27$
$g (3) = - 27$ $g(3)=-27$

Answer 2 · 2017-03-16T00:41:14

$g (3) = - 27$ $g(3)=-27$

Explanation:

Given:

$g (x) = - 2 x^{2} - 9$ $g(x)=-2x^2-9$

Solve if $g (x) = g (3)$ $g(x)=g(3)$

Substitute $3$ $3$ for $x$ $x$ .

$g (3) = - 2 {(3)}^{2} - 9$ $g(3)=-2(3)^2-9$ $\leftarrow$ $larr$ parentheses and exponents first

$g (3) = - 2 \times 9 - 9$ $g(3)=-2xx9-9$ $\leftarrow$ $larr$ multiply $- 2 \times 9$ $-2xx9$

$g (3) = - 18 - 9$ $g(3)=-18-9$

$g (3) = - 27$ $g(3)=-27$

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Given $g (x) = - 2 x^{2} - 9$ $g(x) = -2x^2 - 9$ how do you find g(3)?

2 Answers

Explanation:

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

Given g(x)=−2x2−9g(x) = -2x^2 - 9 how do you find g(3)?

2 Answers

Explanation:

Explanation:

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Impact of this question

Given $g (x) = - 2 x^{2} - 9$ $g(x) = -2x^2 - 9$ how do you find g(3)?