Given $g (x) = 3 x^{2} + 4$ $g(x) = 3x^2 + 4$ how do you find g(-2)?

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Given $g (x) = 3 x^{2} + 4$ $g(x) = 3x^2 + 4$ how do you find g(-2)?

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Answer 1 · 2018-07-06T12:26:49

$g (- 2) = 16$ $g(-2)=16$

Explanation:

$substitute x = - 2 into g (x)$ $"substitute "x=-2" into "g(x)$

$g (- 2) = 3 {(- 2)}^{2} + 4$ $g(color(red)(-2))=3(color(red)(-2))^2+4$

$\times \times = (3 \times 4) + 4$ $color(white)(xxxx)=(3xx4)+4$

$\times \times = 12 + 4 = 16$ $color(white)(xxxx)=12+4=16$

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Given $g (x) = 3 x^{2} + 4$ $g(x) = 3x^2 + 4$ how do you find g(-2)?

1 Answer

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

Given g(x)=3x2+4g(x) = 3x^2 + 4 how do you find g(-2)?

1 Answer

Explanation:

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Impact of this question

Given $g (x) = 3 x^{2} + 4$ $g(x) = 3x^2 + 4$ how do you find g(-2)?