Given $g(x) = 7x - 2$ and $h(x) = 4x^2 + 7$ how do you find (g + h)(-3)?

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Answer 1 · 2016-06-19T15:33:09

Function operations are just as in arithmetic; when adding functions, for example, you must add the functions, combining like terms.

$(g + h)(x) = 4x^2 + 7 + 7x - 2$

$(g + h)(x) = 4x^2 + 7x + 5$

$(g + h)(-3) = 4(-3)^2 + 7(-3) + 5$

$(g +h )(-3) = 36 - 21 + 5$

$(g + h)(-3) = 20$

Hopefully this helps!

Given g(x) = 7x - 2g(x) = 7x - 2 and h(x) = 4x^2 + 7h(x) = 4x^2 + 7 how do you find (g + h)(-3)?