Given $h (x) = \frac{3 x}{2 x - 17}$ $h(x)=(3x)/(2x-17)$ , how do you find h(7)?

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Answer 1 · 2016-10-27T14:46:38

$- 7$ $- 7$

$h (7) = \frac{3 \cdot 7}{2 \cdot 7 - 17} = \frac{21}{- 3} = - 7$ $h(7) = [3 * 7]/[2*7 - 17] = 21/[-3] = - 7$

Answer 2 · 2016-10-27T14:46:39

$h (7) = - 7$ $h(7) = -7$

To find $h (7)$ $h(7)$ you need to substitute $7$ $7$ into every place there is an $x$ $x$ in the equation and solve or:

$h (7) = 3 \cdot \frac{7}{(2 \cdot 7) - 17}$ $h(7) = 3*7 / ((2*7) - 17)$

$h (7) = \frac{21}{14 - 17}$ $h(7) = 21 / (14 - 17)$

$h (7) = \frac{21}{- 3}$ $h(7) = 21 / -3$

$h (7) = - 7$ $h(7) = -7$

Given h(x)=3x2x−17h(x)=(3x)/(2x-17), how do you find h(7)?