Given $h(x) = 5x^2 - 4x$ how do you find h(-3)?

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Answer 1 · 2016-02-27T05:08:26

It is $h(-3)=57$

Hence $h(x)=5x^2-4x$ then just replace $x$ for $-3$

$h(-3)=5*(-3)^2-4*(-3)=>h(-3)=45+12=> h(-3)=57$

Given h(x) = 5x^2 - 4xh(x) = 5x^2 - 4x how do you find h(-3)?